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feat: rerank 不可用时降级到 RRF 算法 #42

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feat: rerank 不可用时降级到 RRF 算法 #42

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18 changes: 16 additions & 2 deletions server/core/rerank/rerank.go
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Original file line number Diff line number Diff line change
Expand Up @@ -46,9 +46,23 @@ var rerankCfg *Conf
func NewRerank(ctx context.Context, query string, docs []*schema.Document, topK int) (output []*schema.Document, err error) {
output, err = rerank(ctx, query, docs, topK)
if err != nil {
return
g.Log().Warningf(ctx, "Rerank remote failed, fallback to RRF: %v", err)
return rrfFallback(docs, topK), nil
}
return
return output, nil
}

// rrfFallback 用 RRF 算法对单路结果（已按原始 score 排好序）重新打分并截断到 topK。
// 单路 RRF 本质上保持原顺序，但把分数统一到可比较的 1/(k+rank) 量纲。
func rrfFallback(docs []*schema.Document, topK int) []*schema.Document {
const k = 60
for rank, doc := range docs {
doc.WithScore(1.0 / float64(k+rank+1))
}
if topK > 0 && len(docs) > topK {
return docs[:topK]
}
return docs
}

func GetConf(ctx context.Context) *Conf {
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