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Peter Krautzberger edited this page Jun 20, 2016 · 2 revisions

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\begin{array}{l}I=\int_0^R{\rho(r)r^2\hspace{0.2em}2\pi r\hspace{0.2em}dr\hspace{0.2em}L=\int_0^R{(\rho_0+\alpha r)r^2}}\hspace{0.2em}2\pi r\hspace{0.2em}dr\hspace{0.2em}L\\hspace{0.2em}\hspace{0.2em}=\frac12\rho_0\pi R^4L+\frac25\alpha\pi R^5L\end{array}

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