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74 lines (63 loc) · 1.28 KB
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/*
Author: Ananthanarayanan R
Section: Algorithms
Question: 242
*/
public class Question242
{
/* Logic 1
public static void sort(char [] arr)
{
int i,j;
for(i=0;i<arr.length;i++)
{
for(j=0;j<arr.length-1;j++)
{
if(arr[j]>arr[j+1])
{
arr[j] = (char)(arr[j]^arr[j+1]);
arr[j+1] = (char)(arr[j]^arr[j+1]);
arr[j] = (char)(arr[j]^arr[j+1]);
}
}
}
}
public static boolean isAnagram(String s, String t)
{
char [] arr1,arr2;
arr1 = s.toCharArray();
arr2 = t.toCharArray();
sort(arr1);
sort(arr2);
String s1 = new String(arr1);
String s2 = new String(arr2);
return s1.equals(s2);
}
*/
//97-122
public static boolean isAnagram(String s, String t)
{
if(s.length() != t.length())
return false;
int [] arr1 = new int[26];
int [] arr2 = new int[26];
int i;
for(i=0;i<s.length();i++)
{
arr1[(int)(s.charAt(i))-97]++;
arr2[(int)(t.charAt(i))-97]++;
}
for(i=0;i<26;i++)
if(arr1[i] != arr2[i])
return false;
return true;
}
public static void main(String[] args)
{
System.out.println("Main Method starts");
String s1,s2;
s1 = "ramu";
s2 = "mura";
System.out.println(isAnagram(s1,s2));
}
}